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Category Archives: 2011 Wisconsin Supreme Court & Recall Elections

The Walker Recall True Vote Model: Implausible Vote Shares Required to Match the Vote

The Walker Recall True Vote Model: Implausible Vote Shares Required to Match the Vote

Richard Charnin

July 11, 2012

This analysis uses the Wisconsin Recall True Vote Model (TVM) to calculate Walker’s share of Obama returning voters that were required to match the state/county recorded vote. It is further evidence that Walker’s recorded margin was implausible and that Barrett very likely won the election.

Walker won in 2010 by 124,638 votes with a 52.3% share. His margin improved in 2012: he won by 171,105 votes and had a 53.1% share.

This worksheet provides a comparative analysis of the 2010 and 2012 elections.

In the recall, Walker’s biggest vote margins (in thousands) were in these counties: Waukesha (96), Washington (36), Brown (21), Ozaukee (20) and Outagamie (18). His biggest margin increases were in Taylor, Trempealeau, Price, Outagamie and Clark. The biggest vote gains were in Waukesha, Milwaukee, Outagamie, Brown and Dane.

In 2008, Obama won Wisconsin with a 56.2% recorded share. But he had 63.3% in the unadjusted exit poll, far beyond the 2.5% margin of error. Although the exit poll is strong evidence that election fraud sharply reduced Obama’s True Vote, we will be conservative and use the recorded vote in this analysis.

It is important to note the sensitivity analysis tables in the TVM. They display vote shares and margins over a range of turnout and vote share assumptions around the base case.

The following DEFAULT assumptions can be overidden on the INPUT sheet:
1) Equal turnout rates for returning Obama and McCain voters.
2) Barrett’s share of returning Obama voters is estimated as an increment applied to his base case 90% Wisconsin share.
3) Shares of New voters are set to the estimated 2008 vote shares.
4) Barrett won 5% of returning McCain voters

The model calculates Walker’s share of Obama returning voters that were required to match the state/county recorded vote.
The “2010-2012” worksheet provides a comparative analysis of the 2010 and 2012 elections

KEY STATE AND COUNTY RESULTS
The very conservative assumption is that Obama’s recorded 56.2% share was his True share. But he did better than that. He had 63.3% in the unadjusted exit poll, therefore Barrett probably did better than his True Vote shown below.

Wisconsin
Obama had 56.2%.
Barrett had 47.1% and lost by 171,000 votes.
Walker needed 23% of returning Obama voters.
Barrett True Vote: 53.6%, 193k margin.

Waukesha
Obama had 36.4%.
Walker had 72.4% and won by 96,000 votes.
Walker True Vote: 65%, a 65k vote margin.
Walker needed 36% of returning Obama voters.

Milwaukee
Obama had 67.3%.
Barrett had 63.2% and won by 107,000 votes.
Barrett True Vote: 65%, 122k margin.
Walker needed 10% of returning Obama voters.

Dane
Obama had 72.8%.
Barrett had 69.1% and won by 99k votes.
Barrett True Vote: 71%, 110k margin.
Walker needed 8% of returning Obama voters.

Outagamie
Obama had 54.9%.
Barrett had 36.1% and lost by 48k votes.
Barrett True Vote: 52% and won by 4,000 votes.
Walker needed 38% of returning Obama voters.

Racine
Obama had 53.1%.
Barrett had 46.7% and lost by 5k votes.
Barrett True Vote: 50.3% and won by 1,000 votes
Walker needed 18% of returning Obama voters.

Rock
Obama had 63.8%.
Barrett had 55.7% and lost by 8k votes.
Barrett True Vote: 61% and won by 15,000 votes.
Walker needed 17% of returning Obama voters.

The Walker Recall County/Ward Database
This spreadsheet database was created to facilitate analysis. A data filter function let’s one quickly view Ward totals for a given county. In addition, vote shares are calculated and automatically sorted.

The data is available as an Excel spreadsheet from Wisconsin GAB. The file consists of 3500 Ward vote records. By itself, it is not very useful since the viewer must scroll through all the records to get the desired county – a time-consuming process.

Take the Election Fraud Quiz.

 

Walker Recall: The Exit Pollster’s MO Never Changes

Richard Charnin
June 9, 2012

The exit pollster’s MO never changes. In the recall, the pundits said it was “too close to call”. I’m quite sure that Barrett was winning, but the media knew the fix was in so they had to keep it close. They knew the actual exit poll numbers would not see the light of day. But they sure called it quickly for Walker, didn’t they?

https://richardcharnin.wordpress.com/2012/06/06/wisconsin-recall-the-adjusted-final-exit-poll-was-forced-to-match-an-unlikely-recorded-vote/

The pollster’s have had plenty of experience in adjusting exit polls to match the vote count.

In 2004, preliminary state exit poll numbers were downloaded from the CNN website by Jonathan Simon. Kerry led by 50-48%. The state polls were already in the process of being matched to the recorded vote. But Bush was winning the vote count – a massive divergence from the exit polls.

We later learned that Kerry led the National Exit Poll from 4pm to midnight. At 4pm (8349 respondents) he led by 51-48%. At 730 pm (11027 respondents) by 51-48%. At 1222am (13047) by 51-47%. But we didn’t see these numbers. They were not meant for public viewing.

The next day, the CNN and NYT websites showed that Bush won the National Exit Poll (13660) by 51-48% – matching the recorded vote. How did the final 613 National Exit Poll respondents enable Bush to flip the vote? The exit pollsters never could answer that one. After all, the flip was mathematically impossible.

The unadjusted 2004 exit polls (state and national) were not released until about a year ago, long after the damage was done. And guess what? Kerry actually won the 13660 respondents! He had 7064 (51.7%), Bush 6414 (47.0%), Other 182 (1.3%).

Someday, probably in 2022, we’ll get to see the unadjusted recall exit poll numbers. In the meantime, here’s the 2004 National Exit Poll Timeline that was “not meant for public viewing”.

https://richardcharnin.wordpress.com/2012/02/21/the-final-2004-national-exit-poll-switched-7-2-of-kerry-responders-to-bush/

And let’s not forget the 2000 selection. The media told us the election was close in Florida and nationwide. But they did not tell us that Gore won the
1) National Exit Poll (13,108 respondents)by 48.5%-46.3%, a 2.7 million margin.
2) 50 state exit polls (58,000 respondents)by 50.8%-45.5%, a 6 million margin.
3) Florida exit poll (1,816 respondents)by 53.4%-43.6%. a 500,000 vote margin.

The media myth is that
1) Gore won the national popular vote by 540,000 votes.
2) Bush won Florida by 537 votes.

All we know is that the Florida recount was halted by the Supreme Court.

Gore won exit polls in the following states – but lost all in the official vote.
He needed just ONE to win the election.
2000: AL AR AZ CO FL GA MO NC NV TN TX VA 

https://richardcharnin.wordpress.com/2011/11/21/unadjusted-state-exit-polls-indicate-that-al-gore-won-a-mini-landslide-in-2000/

– Republican recorded presidential vote shares exceeded the corresponding unadjusted exit poll shares in 226 (82.4%) of the 274 state elections for which there is exit poll data. One would normally expect approximately 137 (50%). The probability is virtually ZERO.

– The exit poll margin of error (described below) was exceeded in 126 (46%) of the 274 polls. The statistical expectation is that the margin of error (MoE) would be exceeded in 14 (5%). The probability is ZERO.

– 123 of the 126 exit polls in which the MoE was exceeded moved to the recorded vote in favor of the Republican (the “red shift”). Just 3 moved in favor of the Democrat (” the blue shift”). There is a ZERO probability that this one-sided shift was due to chance. It is powerful evidence beyond any doubt of pervasive systemic election fraud.

– The Republicans won the recorded vote in 55 states in which the Democrats won the exit poll. Conversely, the Republicans lost the recorded vote in just two states (Iowa and Minnesota in 2000) in which they won the exit poll. If the elections were fair, the number of vote flips would be nearly equal. The probability of this disparity is virtually ZERO.

Calculating the probabilties

The probability P that 55 of 57 exit polls would flip from the Democrats in the exit polls to the Republicans in the recorded vote is given by the Binomial distribution: P= 1-Binomdist(54,57,.5,true)
P= 1.13E-14 = 0.000000000000011 or 1 in 88 trillion!

The probability that the exit poll margin of error would be exceeded in any given state is 5% or 1 in 20. Therefore, approximately 14 of the 274 exit polls would be expected to exceed the margin of error, 7 for the Republican and 7 for the Democrat.

Given the relationship between the exit poll, margin of error and corresponding win probability, we compare the 274 state exit polls to the corresponding recorded votes. The Republicans did better in the recorded vote than in the exit polls in 226 (82.4%) of the 274 elections. The probability of this one-sided red-shift is 3.7E-31 or 1 in 2.7 million trillion trillion.

The MoE was exceeded in 123 exit polls in favor of the Republican – and just 3 for the Democrat. The simple Poisson spreadsheet function calculates the probability P:
P = 5E-106 = Poisson (123, .025*274, false)
P = 1 in 1.8 billion trillion trillion trillion trillion trillion trillion trillion trillion.
The probability is ZERO. There are 106 places to the right of the decimal!
P = .0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 000005

Listen to Stephen Spoonamore – a Republican computer security expert:
http://www.youtube.com/watch?v=ZAyEfovA404&feature=bf_prev&list=PL7EA9A7F25C837D23

 

Wisconsin Recall: The adjusted Final Exit Poll was forced to match an unlikely recorded vote

Richard Charnin
June 6, 2012
Updated: July 11

The media and the exit pollsters have done it again.

Before the first votes were posted, the media reported that based on the exit polls, the election was “too close to call”. But Walker won by 53.2-46.3%, a 173,000 vote margin. Assuming “too close to call” meant that the exit poll indicated a 50/50 split, then there was a significant 7% discrepancy between the unadjusted exit poll and the recorded vote. I believe that Barrett was actually leading the exit polls. Of course, we will never know until the unadjusted exit polls are released. In any case, what caused the unknown red shift?

According to the Wisconsin True Vote Model , Barrett was a likely 54-46% winner. Barrett should have won easily – assuming the caveat of a fair election. But the election was very likely stolen.

Forcing the exit poll to match the recorded vote

The Final Wisconsin adjusted exit poll (2547 respondents) indicated that Walker had 53.0% (see the NY Times link below). The 0.2% difference between the Final and the recorded vote was the result of the standard policy of forcing the unadjusted poll to match the vote.

The pollsters claim that the exit poll had a 4.0% margin of error. But they can’t mean the final adjusted poll because it is always forced to match the recorded vote within 0.5%.

Why did the media not provide the actual unadjusted exit poll demographics? Was it because they knew that they would have to adjust all the crosstabs to match a rigged recorded vote – and did not want the public to view the “adjustments”?

The Fraud Factor

And as is always the case, there was no mention of the fraud factor in the mainstream media. There never is. To the exit pollsters and the media, there is no such thing as election fraud.

The GOP employs overt voter disenfranchisement in plain sight by robocalling voters with false information and having election workers discourage voters from using paper ballots and vote on unverifiable touchscreen DREs. But we are supposed to believe that right-wing voting machine manufacturers would not stoop so low as to write malicious code to covertly flip votes in cyberspace.

In 2010, Walker “won” by 52.2-46.6%, supposedly due to low-Democratic turnout.
Was the election a prologue of the recall?

In the recall, Democrats turned out in droves, they wanted Walker gone. There was no way that the unpopular Governor would match, much less exceed, his 2010 vote – if the votes were counted as cast. But that is a quaint notion considering the overwhelming statistical evidence of systemic election fraud since 1988.

Implausible 2008 returning voters and 2012 vote shares

Obama had a 56.2% recorded share in Wisconsin and 63.3% in the unadjusted exit poll (2.4% margin of error). Assuming Obama had a 60% True Vote share, then to match the recall vote, Walker needed the following:
1) 81% of McCain and 71% of Obama voters turned out.
2) He needed to win 25% of Obama and 95% of McCain voters.
3) He needed 46% of new voters who did not vote in 2010. The 2012 exit poll indicates he had 45% and that new voters comprised 13% of the total vote.

In order to win by his recorded vote, Walker needed a 10% advantage in returning 2008 voters and a 20% advantage in net defections. That is highly implausible.

Exit poll oddities

1) A full 5% of voters were not white or black. But their vote is n/a.
2) Philosophy: 13% of liberals voted for Walker?
3) Party ID: 34% Democrat/ 35% Republican in a progressive state?
4) Labor: Just 62% voted for Barrett?
5) Obama preferred by 51-44%, yet Barrett lost the recall by 53.2-46.3%?
6) Barrett only got 81% of would-be Obama voters?
7)Turnout:47% of recall were returning Walker 2010 and 34% Barrett? That’s a 13% difference. In 2010 Walker “won” by 52.2-46.6%.
8) Urban vote: Barrett had just 62% in big cities?

Margin of error?

The pollsters indicate that there were 2547 exit poll respondents and that the margin of error (MoE) was +/-4%. Presumably, this includes a 30% cluster factor.

The adjusted poll had a zero MoE since it was forced to match the recorded vote. What is the point of mentioning a MoE if the exit poll is adjusted to match the recorded vote?

The pollsters must be referring to the unadjusted exit poll, but of course that is not for public viewing. In any case, the 4.0% MoE is too high, considering the number of respondents (n).

The simple formula is: MoE =.98/sqrt(n). Adding a 30% cluster factor, the theoretical MoE is 2.6%= 1.3*.98/sqrt(2547). So how did the pollsters come up with the 4.0% MoE?

If we had unadjusted exit poll data, the margin of error would be applied to determine the interval where the vote share would be expected to fall 95% of the time. That’s why unadjusted exit polls are necessary. The standard practice of forcing the exit poll to match the recorded vote implicitly assumes zero fraud, i.e. the recorded vote is identical to the True Vote. It never is.

The Ultimate Smoking Gun: Unadjusted state presidential exit polls (1988-2008)

July 11 Update: There are 274 state exit polls listed in the Roper archive for 1988-2008 (only 24 are listed for 1988). I originally used the True Vote Model to estimate the 26 missing 1988 exit polls. Dr. Bob Fitrakis, writing in The Free Press, referred to the earlier probability calculations in an excellent article: Wisconsin: None Dare Call it Vote Rigging

Here are the revised numbers, based on 274 exit polls:

– Republican recorded presidential vote shares exceeded the corresponding unadjusted exit poll shares in 232 (85%) of the 274 state elections for which there is exit poll data. One would normally expect approximately 137 (50%). The probability is virtually ZERO.

– The exit poll margin of error (described below) was exceeded in 135 (49%) of the 274 polls. The statistical expectation is that the margin of error (MoE) would be exceeded in 14 (5%). The probability is ZERO.

– 131 of the 135 exit polls in which the MoE was exceeded moved to the recorded vote in favor of the Republican (the “red shift”).  There is a ZERO probability that this one-sided shift was due to chance. It is powerful evidence beyond any doubt of pervasive systemic election fraud.

– The Republicans won the recorded vote in 55 states in which the Democrats won the exit poll. Conversely, the Republicans lost the recorded vote in just two states (Iowa and Minnesota in 2000) in which they won the exit poll. If the elections were fair, the number of vote flips would be nearly equal. The probability of this disparity is virtually ZERO.

Calculating the probabilties

The probability P that 55 of 57 exit polls would flip from the Democrats in the exit polls to the Republicans in the recorded vote is given by the Binomial distribution:

P= 1-Binomdist(54,57,.5,true)
P= 1.13E-14 = 0.000000000000011 or 1 in 88 trillion!

The probability that the exit poll margin of error would be exceeded is 5% or 1 in 20. Therefore, approximately 14 of the 274 exit polls would be expected to exceed the margin of error, 7 for the Republican and 7 for the Democrat.

Given the relationship between the exit poll, margin of error and corresponding win probability, we compare the 274 state exit polls to the corresponding recorded votes. The Republicans did better in the recorded vote than in the exit polls in 232 of the 274 elections. The probability of this one-sided red-shift is 9E-35 or 1 in 100 billion trillion trillion.

The MoE was exceeded in 131 exit polls in favor of the Republican – and just 4 for the Democrat. The simple Poisson spreadsheet function calculates the probability P:
P = 3.74E-116 = Poisson (131, .025*274, false)
P = .0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 00000374

1988-2008 Red-shift Summary (274 exit polls)
The following table lists the
a) Number of states in which the exit poll red-shifted to the Republican,
b) Number of states which red-shifted beyond the margin of error,
c) Probability of n states red-shifting beyond the MoE,
d) Democratic unadjusted aggregate state exit poll share,
e) Democratic recorded share,
f) Difference between Democratic exit poll and recorded share.

Year RS >MoE Probability.... Exit Vote Diff
1988 21.. 12... 2.5E-12..... 50.3 45.7 4.6 Dukakis may have won
1992 45.. 27... 1.1E-26..... 47.6 43.0 4.6 Clinton landslide
1996 44.. 19... 2.5E-15..... 52.6 49.3 3.3 Clinton landslide
2000 34.. 17... 4.9E-13..... 50.8 48.4 2.4 Gore win stolen
2004 42.. 23... 3.5E-20..... 51.1 48.3 2.8 Kerry landslide stolen
2008 46.. 37... 2.4E-39..... 58.0 52.9 5.1 Obama landslide denied

Total 232. 135. 3.7E-116…. 51.7 47.9 3.8 Exact match to the Nat Exit Poll

Note: 274 exit polls from 1988-2008
(24 in 1988, 50 in each of the 1992-2008 elections)

The conventional wisdom is very conventional – and very misleading:
http://www.huffingtonpost.com/2012/06/05/wisconsin-recall-vote_n_1572662.html

The NY Times Election site has the FINAL, adjusted exit poll crosstabs.
http://www.nytimes.com/interactive/2012/06/05/us/politics/wisconsin-recall-exit-polls.html

 

The Walker Recall: Is the Past Prologue?

The Walker Recall: Is the Past Prologue?

Richard Charnin
May 24, 2012

In a previous Walker recall election analysis the Wisconsin True Vote Model indicated that Barrett would win a fair election with 53-54%. The purpose of this analysis is to determine what it took for Walker to win in 2010. This information may provide insight into what we can expect in the recall.

The 2010 Election

Approximately 69% of 2008 voters turned out in the 2010 Wisconsin Governor race. Walker defeated Barrett by 125,000 recorded votes (52.2-46.6%). The exit poll was forced to match the recorded vote. That is standard operating procedure.

In order to force the exit poll to match the vote, it required that 49% of the 2010 electorate were returning Obama voters and 43% returning McCain voters. The 6% spread is 8% below Obama’s recorded margin and a whopping 22% below his exit poll margin. The spread implies that 66% of Obama voters and 77% of McCain voters returned in 2010 – a net 11% turnout advantage to Walker.

In the poll, Barrett had 83% of Obama voters and 7% of McCain voters – a net 10% defection of returning Obama voters. Walker had 16% of Obama voters and 93% of McCain voters. In addition, 3% were returning third-party and 5% did not vote in 2008 – but the vote shares were n/a. A simple calculation shows that in order to match the recorded vote, Walker needed to win new and returning third-party voters by a 20% margin.

To summarize, in order to match the recorded vote, the adjusted Final 2010 Wisconsin exit poll assumed…
1) There was ZERO fraud in 2008.
2) McCain returning voter turnout exceeded Obama turnout by 11%.
3) 16% of Obama voters defected to Walker and 7% of McCain voters defected to Barrett.
4) Walker had a 20% margin among new and returning 2008 third-party voters.

The 2012 True Vote Model

The base case assumption in the 2012 Wisconsin Recall True Vote Model that Obama had a 60% vote share is conservative. He had 63.3% in the Wisconsin exit poll (2545 respondents) but just 56.2% recorded – triple the 2.4% margin of error. There is a virtual 100% probability that Obama’s True share exceeded 60%. In other words, the 2008 election was likely extremely fraudulent, but not so fraudulent as to cause Obama to lose Wisconsin.

Unlike final national and state exit polls that are adjusted to conform to the recorded vote (and implicitly assume zero fraud), the True Vote Model is based on a feasible estimated turnout of previous election voters and best vote share estimates of returning and new voters.

The model calculates various scenarios (“sensitivity analysis”) of 2008 election voter turnout in 2012 based on the 2008 a) recorded vote, b) unadjusted exit poll or 3) estimated True Vote.

What does this portend for the recall?
Three scenarios:

1) Fraud: Walker wins by a similar margin as he did in 2010 (125,000 votes)
2) Fraud: But not enough to steal the election. Barrett wins by 70,000.
3) No fraud. Barrett wins by at least 160,000.

1988-2008: the 8% unadjusted exit poll margin discrepancy

Unadjusted state and national exit poll data is available on the Roper website. The Democrats won the aggregate 1988-2008 presidential unadjusted exit polls by 52-42% -an 8% discrepancy in margin from the 48-46% recorded vote. Bloggers, pollsters and academics are apparently unaware that the data even exists. After all, the NY Times and CNN never reported that fact. But they do show exit polls adjusted to conform to bogus recorded votes on their websites.

How many voters are aware that Obama won the Unadjusted National Exit Poll (17,836 respondents) by a 61-37% margin? Or that he won the state aggregate exit polls (82,388 respondents) by 58-40.5%? The Final 2008 National Exit Poll was forced to match the recorded vote by implying an impossible 103% turnout of living Bush 2004 voters and 12 million more returning Bush than Kerry voters.

In every election the pollsters force state and national exit polls to match the recorded vote. They accomplish this by adjusting all demographic crosstabs that are displayed in the various mainstream media election sites. As a result of the forced match to the recorded vote, the “pristine” demographic percentages are contaminated. In other words, by matching to the recorded vote, final exit polls disguise the true intent of various classes of voters.

 

Wisconsin Governor Recall: A True Vote Model Analysis

Wisconsin Governor Recall: A True Vote Model Analysis

Richard Charnin
May 3, 2012

Barrett should win easily – assuming ZERO fraud.
But there WILL be fraud. So let’s look at the scenarios.

Let’s check out the Wisconsin True Vote Model.

In 2008, Obama had a 56.2% recorded vote share in Wisconsin. But he had 63.2% in the unadjusted exit poll (n=2,545 respondents). The poll had a 2.43% margin of error (including a 30% “cluster effect”).

MoE = (1+cluster) * Stdev * sqrt(p*(1-p)/n)
MoE = 2.43% = 1.3 * 1.96 * sqrt(.639*.361/2545)

There is a near 100% probability that Obama’s True Wisconsin share exceeded 60%:

All of the following scenarios assume that Obama had a 60% WI share.
___________________________________________________________________________

CONSERVATIVE Base Case assumptions (favoring Walker)

Returning 2008 Voter Turnout (net 5% to Walker)
65% Obama voter turnout
70% McCain voter turnout

Voter Defection (net 5% to Walker)
Barrett wins 90% of returning Obama voters
Barrett wins 5% of returning McCain voters

Barrett wins by 54.6-45.4% (198,000 votes)
Walker needs to steal 8.4% of Democratic votes to win.

___________________________________________________________________________

Zero Net Turnout and Voter Defection Scenarios

1. Equal 70% turnout; Barrett wins 90% of Obama and 5% of McCain voters
Barrett has 56.2% and wins by 267,000 votes.
Walker needs to steal 11% to win.

2. Equal 70% Turnout; Barrett wins 95% of Obama and 5% of McCain voters.
Barrett has 59% and wins by 387,000 votes.
Walker needs to steal 15% to win.

___________________________________________________________________________

Democratic Worst Case Scenarios

1. Voter Turnout: 65% of Obama; 70% of McCain
Barrett wins 85% of Obama voters and 0% of McCain voters.
Barrett has 50.2% and wins by 9,000 votes.

2. Voter Turnout: 60% Obama; 75% McCain
Barrett wins 90% of Obama voters and 5% of McCain voters.
Barrett has 51.8% and wins by 80,000 votes.

___________________________________________________________________________

Implausible Scenarios required for Walker to win a fair election

1. Voter Turnout: 55% Obama; 80% McCain
Vote share: Barrett wins 90% of Obama voters and 5% of McCain voters.
Barrett has 49.1% and loses by 38,000.

2. Voter Turnout: 65% Obama; 70% McCain
Vote share: Barrett wins 80% of Obama voters and 5% of McCain voters.
Barrett has 49.4% and loses by 25,000.

 

Wisconsin Recalls: Exit Polls and the True Vote Model

Sept 7, 2011

In each of the five Citizen Exit Polls conducted in two Wisconsin districts, the Democrats did much better than the official count (67.8% vs. 52.4% on average). Why the large discrepancies? Are the polls to be believed? This analysis provides a possible explanation, keeping in mind that it is based on a limited number of exit poll locations.

The Wisconsin Recall True Vote Model
https://docs.google.com/spreadsheet/ccc?key=0AjAk1JUWDMyRdDRwcWRPTUZoZk53YUlxOEVMT0FnX3c#gid=11

It is important to understand the difference between the Wisconsin Citizen exit polls and corporate sponsored state and national exit polls in prior elections. The Citizen polls had a very simple aim: to compare how respondents said they voted to the official count.

State and National Exit Polls: Forced to Match the Recorded Vote
Corporate state and national exit polls are designed to determine how various demographic groups voted. The National Exit Pool (NEP) is the consortium of six media giants that funds state and national exit polls.
The NEP uses stratified sampling to select precinct locations that are representative of the voting population.

It is standard operating procedure to force Final state and national exit polls to match the recorded vote. It is also standard policy for the NEP to keep “unadjusted” precinct exit poll data hidden from the public, claiming the need to protect voter “privacy”. It’s a canard; exit poll responders do not reveal their identity. There is no excuse for suppressing the release of unadjusted precinct exit poll data.

Recall Exit Poll Discrepancies
In three strong Democratic recall locations, Democratic exit poll shares (78.8%) were significantly higher than the vote counts (66.9%). Shorewood was 10.9% higher, Pardeeville 8.5% and Baraboo 15.8%. The True Vote Model (TVM) closely matched the recorded votes. Overall voter participation was 52%. If the vote counts were correct, 61% of Democrats and 33% of Republicans responded. Republican voters may have been reluctant to respond in these heavily Democratic locations. If that was the case, then the exit polls overstated the True Democratic vote.

In the two strong Republican locations (Butler and Menomonee Falls), the Democrats had 43.1% in the exit polls compared to 31.5% in the count(16.5% higher in Butler, 11.0% in Menomonee). In the TVM, the Democrats did 11.0% and 8.3% better, respectively. Overall just 33% of voters participated. If the vote counts were correct, then 45% of Democrats and 28% of Republicans responded – an implausible Democratic participation in these strong GOP locations. Therefore, it is likely that the votes were miscounted and the exit polls were close to the True Vote.

The aggregate Democratic True Vote share was 55.2%, a very close match to the 55.5% aggregate share calculated based on equal Democratic and Republican response in each location.

The discrepancies could also have been due to a combination of vote miscounts and differential response. Assuming equal Democratic and Republican response rates, Democratic shares were 73.0% (6.1% higher than recorded) in Democratic locations and 35.4% in Republican locations (3.9% higher).

Republican Exit Poll Response Required to Match Recorded Vote
The total Democratic exit poll response rate was 57%; the Republican rate was 30%. Democratic response exceeded Republican response in each of the five locations. What if the overall Republican response was also 57%? What would the response have to be in each location for the exit poll to match the recorded vote (52.4% Dem, 47.6% Rep)? Using the Excel Solver algorithm, the required Republican response was derived (Democratic response was held constant to the actual exit poll). Republican response was constrained to exceed Democratic response in Menomonee Falls and Butler. The required response rates were not plausible (see the table below). Republican response exceeded Democratic response in 4 of the 5 locations (including Democratic strongholds Pardeeville and Shorewood). In Pardeeville, 100% of Republican voters responded.

Exit Poll Refusal Rates
We define Exit Poll refusals as the difference between the total number of non-responders and the number of non-responders required to match the recorded vote. The refusal rate is the ratio of refusals to the recorded vote. The average Republican refusal rate in Democratic locations was 18.8%: Baraboo 16.6%, Pardeeville 12.9%, Shorewood 22.5%. In Republican locations, the rate was 5.6%: Menomonee Falls 5.9%, Butler 5.2%. Republican voters were four times more likely to refuse an exit poll interview in Democratic than in Republican locations.

Based on the True Vote Model and the exit polls, it is very likely that the District 8 and 14 recall elections were stolen. The Republicans control the state senate by a 17-16 majority, but the Democrats should be in control by 18-15.

True Vote Model
The TVM requires an estimate of the True Vote in the previous election in order to determine a plausible mix of returning voters. In 2008, Obama had a 56.2% recorded vote share in Wisconsin, but he had a whopping 63.3% in the unadjusted exit poll. The margin of error was 2.4% (including a 30% cluster effect) for the 2545 respondents. It is obvious that using a miscounted recorded vote from the previous election as a basis for forecasting or post-election analysis will produce a fraudulent result in the current election.

These were the base case assumptions used in the TVM:
1) Equal percentage turnout of Obama/McCain voters.
2) Zero net defection: Democrats win 95% of returning Obama voters, Republicans win 95% of McCain voters.
3) New voters broke for the Democrats and Republicans in the same proportion as the 2008 recorded vote.

For each exit poll location, a sensitivity analysis table displays Democratic vote shares based on nine scenario combinations of returning Obama and McCain voters. The base case scenario is the central cell of the 3×3 table.

2004 Exit Polls
In 2004, there were 1480 exit poll precinct polling locations nationwide. More than 76,000 voters participated. To explain the average 6.5% exit poll discrepancy, the exit pollsters hypothesized that 56 Kerry voters participated for every 50 Bush voters. They provided no evidence for this. They did not consider that the discrepancies may have been due to Election Fraud. The so-called reluctant Bush responder (rBr) theory was refuted by the exit pollster’s own data which showed that exit poll response was higher in Bush strongholds than Kerry strongholds.

Link to the source data tables:
http://richardcharnin.com/WIRecallExitTrueRecorded.htm

 

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Nine Wisconsin Recalls: A True Vote Analysis

A Statistical Analysis of the Wisconsin Recall Elections

Richard Charnin

Aug. 17, 2011

The numerical analysis is based on the Wisconsin Recall True Vote Model.
http://richardcharnin.com/TrueVoteModels.htm

The Democrats won 5 of the 9 recall elections and won the overall popular vote with a 50.5% share. In 2008, Obama won all 9 districts with a 54.5% share.

The Republicans won 4 of the 6 GOP districts with 55.2%. Obama had 51.5% in the four districts. To accomplish this, there had to be an implausibly low Obama voter turnout and/or an implausibly high defection of Obama voters.

The Democrats did 3.2% better than Obama in the three Democratic recalls, but 5.4% worse in the 6 GOP recalls, an implausible difference.

In the GOP districts, voter turnout was 65% of the 2008 presidential election; it was 48% in Democratic districts.

These anomalies, combined with documented evidence of voting irregularities and exit poll results, are very strong indicators of Election Fraud. It is very likely that the Democrats won at least seven of the nine elections.

In the 6 GOP recall elections, 65% of Obama and McCain voters returned to vote. Assuming zero net defection, approximately 58% of Obama voters and 85% of McCain voters turned out. That is a very implausible difference. Assuming equal 65% turnout, the Democrats won 82% of Obama voters and Republicans won 92% of McCain voters – an implausible 10% net Obama defection.

In the 2 GOP districts won by the Democrats with an average 53.2% share, Obama had 55.9%. Total turnout was 66%. Approximately 63% of Obama voters turned out. That is plausible. Assuming equal turnout, the Democrats won 91% of Obama voters and 5% of McCain voters. Very plausible.

The 3 Democratic recall elections were landslides. The Democrats had a 58.8% aggregate share. Obama had 55.5%. Approximately 48% of 2008 voters turned out. Assuming zero net defection, 52% were Obama and 44% McCain. That is plausible. Assuming equal 48% turnout, the Democrats won 98% of Obama and 8% of McCain voters (6% net McCain defection). Also plausible.

 

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