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2014 NC Senate: Election models indicate that it was likely stolen

Richard Charnin
Jan. 28, 2016

Election Models indicate that the 2014 North Carolina senate election was likely stolen.
Willis (R) defeated Hagan (D) by 45,000 votes (48.8-47.3%).

I. True Vote Model

Given: Obama lost NC in 2012 by 92,000 recorded votes (50.4-48.4%).
Hagan wins by 17,000 votes (48.5-47.9%)

Assume Obama won the True Vote by 185,000 votes (51.4-47.4%),
Hagan wins by 155,000 votes (50.9-45.5%) 

Base Case Assumptions
Assume Obama won in 2012 by 51.4-47.4%.

1) 60% turnout of Obama and Romney voters,
2) Hagan had 92% of returning Obama voters
3) Willis had  90% of Romney voters
4) Hagan had 47% and Willis 45% of voters who did not vote in 2012.
Hagan  wins by 155,000 votes: 50.9-45.9%

Sensitivity analysis I: Returning vote shares

Worst case scenario: Hagan has 88% of returning Obama and 5% of Romney voters.
Hagan loses by 4,000 votes with 48.1%.

Best case scenario: Hagan has 96% of Obama and 9% of Romney voters.
Hagan wins by 314,000 votes with 53.6%.

Sensitivity analysis II: 2012 voter turnout in 2014

Worst case scenario: 58% of Obama and 62% of Romney voters return in 2014.
Hagan wins by 81,000 votes with 49.6%.

Best case scenario: 62% of Obama and 58% of Romney voters return in 2014.
Hagan wins by 230,000 votes with 52.1%.

II. Voter Turnout Model

Party registration: Democrats 41.7%- Republicans 30.4%- Independents 27.8%
Exit Poll Party-ID: Democrats 36.0%- Republicans 35.0%- Independents 29.0%
Party-ID was adjusted to force a match to the recorded vote

Assumptions:
Party Registration split
61% of Democrats and 61% of Republicans turned out.
Hagan wins by 50.9-45.4% (161,000 votes).

III. Uncounted Vote Model

Given: 260,000 of 3.17 million votes cast were uncounted.
Assumption: Hagan had 75% of the uncounted votes.
Hagan wins by 206,000 votes (51.6-45.1%)

Reclaiming Science: The JFK Conspiracy
Matrix of Deceit: Forcing Pre-election and Exit Polls to Match Fraudulent Vote Counts
Proving Election Fraud: Phantom Voters, Uncounted Votes and the National Exit Poll
LINKS TO WEB/BLOG POSTS FROM 2004

Election Fraud Overview

https://docs.google.com/document/d/1NoLTeS9HflwTNJgi5n8nNLdomjxh6eKjoy5FuOmqsVU/pub

 

 

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Posted by on January 28, 2016 in 2014 Elections, Uncategorized

 

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2014 VT Governor: The Democrat won, but why was it so close?

Richard Charnin
Jan. 27, 2016

2014 VT Governor: The Democrat won, but why was it so close?

Three election models indicate that the 2014 Vermont governor election was almost stolen. Shumlin (D) defeated Milne (R) by just 2,000 votes (46.4-45.3%)

Obama won Vermont in 2012 by 95,000 recorded votes (66.1-31.0%).

True Vote Model

Base Case Assumptions
1) 55% turnout of Obama and 65% turnout of Romney voters
2) Shumlin had 86% of returning Obama voters
3) Milne had 93% of Romney voters
4) Shumlin and Milne each had 40% of voters who did not vote in 2012.

Shumlin won by 27,000 votes: 54.3-40.2%
In order to match the recorded vote, Milne needed 22.4% of Obama voters.

Sensitivity analysis I: Returning vote shares
Worst case scenario: Shumlin has 82% of returning Obama and 2% of Romney voters.
Shumlin wins by 16,000 votes with 51.5%.

Best case scenario: Shumlin has 90% of Obama and 6% of Romney voters.
Shumlin wins by 38,000 votes with 57.1%.

Sensitivity analysis II: 2012 voter turnout in 2014
Worst case scenario: 53% of Obama and 67% of Romney voters return in 2014.
Shumlin wins by 22,000 votes with 53.0%.

Best case scenario: 57% of Obama and 63% of Romney voters return in 2014.
Shumlin wins by 32,000 votes with 55.6%.

Voter Turnout Model

Party registration: Democrats 47%- Republicans 31%- Independents 22%
59.9% of registered voters turned out.

Assumption: 59.9% of Democrats and 59.9% of Republicans turned out.
Shumlin wins by 53.4-39.2%

To match the recorded vote, Milne needed 19% of Democrats, 89% of Republicans and 40% of Independents.

Uncounted Vote Model

Given: 11,000 of 205,000 votes cast were uncounted.
Assumption: Shumlin had 75% of the uncounted votes.
Shumlin won by 55.4-38.9%.

Look inside the books:
Reclaiming Science: The JFK Conspiracy
Matrix of Deceit: Forcing Pre-election and Exit Polls to Match Fraudulent Vote Counts
Proving Election Fraud: Phantom Voters, Uncounted Votes and the National Exit Poll
LINKS TO WEB/BLOG POSTS FROM 2004

 
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Posted by on January 27, 2016 in 2014 Elections, Uncategorized

 

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Oregon 2014 Governor: Models confirm prior analysis of honest elections

Richard Charnin
Jan. 27, 2016

Oregon 2014 Governor: Models confirm prior analysis of honest elections
Kitzhaber (D) defeated Richardson (R ) by 85,000 votes (50.3-44.2%)

Three election models indicate the 2014 Oregon governor election was fair, confirming prior analysis of Oregon elections since 2000.

http://sos.oregon.gov/elections/Pages/electionsstatistics.aspx

True Vote Model

Obama won Oregon in 2012 by 206,000  votes (54.2-42.1%).  

Base Case Assumptions

1) 75% turnout of Obama and Romney voters,
2) Kitzhaber had 87% of returning Obama voters
3) Richardson had  90% of Romney voters
4) Kitzhaber had 44% and Richardson 46% of voters who did not vote in 2012.

Base Case: Kitzhaber won by 91,000 votes: 50.3-44.2%

Sensitivity analysis I: Returning vote shares
Worst case scenario: Kitzhaber has 83% of returning Obama and 3% of Romney voters.
Kitzhaber wins by 11,000 votes with 47.6%.

Best case scenario: KItzhaber has 91% of Obama and 7% of Romney voters.
Kitzhaber wins by 170,000 votes with 53.0%.

Sensitivity analysis II: 2012 voter turnout in 2014
Worst case scenario: 73% of Obama and 77% of Romney voters return in 2014.
Kitzhaber wins by 63,000 votes with 49.4%.

Best case scenario: 77% of Obama and 73% of Romney voters return in 2014.
Kitzhaber wins by 118,000 votes with 51.3%.

Voter Turnout Model

Party registration: Democrats 37.8%- Republicans 29.9%- Independents 32.3%
Exit Poll Party-ID: Democrats 36.0%- Republicans 24.0%- Independents 40.0%

67.5% of registered voters turned out.
Assumptions: 67.5% of Democrats and 67.5% of Republicans turned out.
Kitzhaber wins by 50.3-44.1% (91,000 votes).

Look inside the books:
Reclaiming Science: The JFK Conspiracy
Matrix of Deceit: Forcing Pre-election and Exit Polls to Match Fraudulent Vote Counts
Proving Election Fraud: Phantom Voters, Uncounted Votes and the National Exit Poll
LINKS TO WEB/BLOG POSTS FROM 2004

 
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Posted by on January 27, 2016 in 2014 Elections, Uncategorized

 

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Maine 2014 Governor: Three models indicate a stolen election

Richard Charnin
Jan. 26, 2016

Three election models  indicate that the 2014 Maine governor election was likely stolen.

Lepage (R) defeated Michaud (D) by 30,000 votes (48.3-43.3%)
Obama won Maine in 2012 by 109,000 recorded votes (56.3-41.0%).  

True Vote Model

Base Case Assumptions
1) 75% turnout of Obama and Romney voters,
2) Michaud had 86% of returning Obama voters
3) Lepage had  87% of Romney voters
4) Michaud  had 45% and Lepage 39% of voters who did not vote in 2012.

Base Case: Michaud won by 51,000 votes: 50.3-41.2%
In order to match the recorded vote, Lepage needed 23.7% of Obama voters.

Sensitivity analysis I: Returning vote shares

Worst case scenario: Michaud has 82% of returning Obama and 2% of Romney voters.
Michaud wins by 23,000 votes with 47.7%.

Best case scenario: Michaud has 90% of Obama and 6% of Romney voters.
Michaud wins by 88,000 votes with 53.0%.

Sensitivity analysis II: 2012 voter turnout in 2014

Worst case scenario: 73% of Obama and 77% of Romney voters return in 2014.
Michaud wins by 44,000 votes with 49.4%.

Best case scenario: 77% of Obama and 73% of Romney voters return in 2014.
Michaud wins by 67,000 votes with 51.3%.

Voter Turnout Model

Party registration: Democrats 31.9%- Republicans 27.1%- Independents 41.0%
Exit Poll Party-ID: Democrats 30.0%- Republicans 31.0%- Independents 39.0%
76.2% of registered voters turned out.

Assumptions: 74% of Democrats and 78.8% of Republicans turned out.
Michaud wins by 49.2-42.3% (42,000 votes),

To match the recorded vote, Lepage needed 29% of  Democrats, 87% of Republicans and 37% of Independents.

Uncounted Vote Model

Given: 33,000 of 642,000 votes cast were uncounted.
Assumption: Michaud had 75% of the uncounted votes.
Michaud won by 71,000 votes (51.1-40.0%)

 

Look inside the books:
Reclaiming Science: The JFK Conspiracy
Matrix of Deceit: Forcing Pre-election and Exit Polls to Match Fraudulent Vote Counts
Proving Election Fraud: Phantom Voters, Uncounted Votes and the National Exit Poll
LINKS TO WEB/BLOG POSTS FROM 2004

 
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Posted by on January 26, 2016 in 2014 Elections, Uncategorized

 

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2014 Michigan Governor: Three election models indicate likely fraud

2014 Michigan Governor: Three election models indicate likely fraud

Richard Charnin
Jan. 25, 2016

Reclaiming Science: The JFK Conspiracy
Matrix of Deceit: Forcing Pre-election and Exit Polls to Match Fraudulent Vote Counts

An analysis of three election models indicates that the 2014 Michigan governor election may have been stolen.

Snyder (R ) defeated Schauer (D) by 130,000 votes (51.0-46.8%)

True Vote Model

Given: Obama won Michigan in 2012 by 450,000 recorded votes (54.1-44.6%).  
This is conservative; he likely did better.

Base Case Assumptions
1) 60% turnout of Obama and Romney voters,
2) Schauer had 91% of returning Obama voters
3) Snyder had  91% of Romney voters
4) Schauer and Snyder each had 48% of voters who did not vote in 2012.

Base Case True Vote: Schauer won by 223,000 votes: 52.4-45.3%
In order to match the recorded vote, Snyder needed 18.7% of Obama voters

Sensitivity analysis I: Returning vote shares

Worse case scenario: Schauer has 87% of returning Obama and 5% of Romney voters.
Schauer wins by 52,000 votes with 49.7%.

Best case scenario: Schauer has 95% of Obama and 9% of Romney voters.
Schauer wins by 393,000 votes with 55.1%.

Sensitivity analysis II: 2012 voter turnout in 2014

Worse case scenario: 58% of Obama and 62% of Romney voters return in 2014.
Schauer wins by 145,000 votes with 51.2%.

Best case scenario: 62% of Obama and 58% of Romney voters return in 2014.
Schauer wins by 300,000 votes with 53.7%.

Voter Turnout Model

Exit Poll Party-ID: In order to match the recorded vote, Snyder needed 9.6% of Democrats, 91% of Republicans and a whopping 64% of Independents.

Actual Party registration: Democrats 44%- Republicans 37%- Independents 19%
Given: 60.8% of registered voters turned out.

Assumptions: 59% of Democrats and 63% of Republicans turned out.
Schauer wins by 50.4-47.4% (94,000 votes)

Uncounted Vote Model

Given: 278 thousand of 3.416 million votes cast were uncounted.

Assumption: Schauer had 75% of the uncounted votes.
Schauer won by 368,000 votes (54.3-43.5%)

Jan BenDor writes:

We already knew of this fraud from our analysis of the Detroit Mayoral election in 2009 and the Gubernatorial election in 2010. The ES&S ballot programmers, who serviced all brands of the machines, were all former Michigan Republican officials or their employees. Only three counties had their own in-house ballot programmers sworn to an oath to obey the laws and Constitution. In addition, the state requires no accounting for unused blank ballots left in the custody of the elected local Clerk. This provides a huge opportunity for absentee ballot fraud, and ballot chaining.

In 2004, when counties were ordered to decide on one brand of optical scan machine, in order to spend the state’s HAVA grant, the Republican Clerks went with their favorites, Diebold and ES&S. Sequoia was left out in the cold–it had the best security. I asked the vendor what happened to his bid. The owner of the company, Barry Miller, told me, “I have been a Republican all of my life. But I guess I didn’t give enough money to their candidates.”

 
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Posted by on January 25, 2016 in 2014 Elections, Uncategorized

 

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JFK Conspiracy and Systemic Election Fraud Analysis